To solve this we are going to use the formula for compounded interest: [tex]A=P(1+ \frac{r}{n})^{nt}[/tex]
where
[tex]A[/tex] is the final amount after [tex]t[/tex] years
[tex]P[/tex] is the initial amount
[tex]r[/tex] is the interest rate in decimal form
[tex]n[/tex] is the number of times the interest is compounded per year
[tex]t[/tex] is the time in years
We know for our problem that [tex]P=1380[/tex], [tex]r= \frac{5}{100} =0.05[/tex], and [tex]t=3[/tex]. Since the interest is compounded daily, it is compounded 365 times in year; therefore, [tex]n=365[/tex]. Lets replace those values in our formula to find [tex]A[/tex]:
[tex]A=P(1+ \frac{r}{n})^{nt}[/tex]
[tex]A=1380(1+ \frac{0.05}{365})^{(365)(3)} [/tex]
[tex]A=1603.31[/tex]
We can conclude the amount in Diane's after 3 years will be $1,603.31