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First of all, your second line would have the same slope : 3

Then we know that this line passes throught the point (2, -4)

The equation for this line is like :   
[tex]y'=mx+p'[/tex]

[tex]y'=-4\\m=3\\x=2\\\\-4=3\times(2)+p\\-4=6+p\\p=-4-6\\p=-10\\[/tex]

So the equation in slope form for the line parallel to y = 3x+7 is : y' = 3x - 10

Step-by-step explanation: