Answer:
A. 110 N forward
[tex]F_{net} = 110 N[/tex]
Explanation:
As we know that force is a vector quantity so here we can say that
forward force is positive force while backward force on car is negative force
So here since John push the car in forward direction so we have
[tex]F_1 = 290 N[/tex]
Now bob push the car in backward direction so
[tex]F_2 = -180 N[/tex]
now the net force is given as
[tex]\vec F = \vec F_1 + \vec F_2[/tex]
[tex]\vec F = 290 - 180 = 110 N[/tex]
so net force on car will be 110 N in forward direction