Question

PLZ do not delete these questions. I will give 50 points for the question, a Brainliest, a thanks, and a five stars rate.

1. The Soup Company wants to package its soup in a new can which is in the shape of a cylinder. The new label will completely cover the sides of the can but not the top and bottom of the can. The company has four choices for the cans. Which can will need the least amount of paper to make the new label?

Soup Can Choices
Can Radius Height
A 2 inches 6 inches
B 2.5 inches 5 inches
C 3 inches 4 inches
D 3.2 inches 3 inches

Recall the formula LA= 2 pi rh.
Can A
Can B
Can C
Can D

2. A cylinder has a radius of 6 inches and a height of 15 inches. What is the surface area of the cylinder? Express the answer in terms of pi.

The first picture goes to this question.

Recall the formula SA= 2 pi r^2+ 2 pi rh.
216 pi in.^2
252 pi in.^2
630 pi in.^2
648 pi in.^2

3. What is the volume of the cylinder? Express the answer in terms of pi.

The second picture goes to this question.

Recall the formula V= pi r^2 h.
288 pi cm^3
1152 pi cm^3
1296 pi cm^3
2592 pi cm^3

4. A cylinder has a diameter of 40 feet and a height of 32 feet. What is the surface area of the cylinder? Express the answer in terms of pi.

Recall the formula SA= 2 pi r^2+ 2 pi rh
1320 pi ft. ^2
1792 pi ft. ^2
2080 pi ft. ^2
2640 pi ft. ^2

5. A cylinder has a radius of 6 inches and is 15 inches tall. What is the approximate volume of the cylinder? Express the answer in terms of pi.

The third picture is for this question.

Recall the formula V= pi r^2 h.
90 pi in. ^3
540 pi in. ^3
1350 pi in. ^3
2160 pi in. ^3

Answer 1

Answer:

Ques 1)

CAN D

Ques 2)

252 pi in.^2

Ques 3)

288 pi cm^3

Ques 4)

2080 pi ft. ^2

Ques 5)

540 pi in. ^3

Step-by-step explanation:

Let r denote the radius of the cylinder.

and h denote the height of the cylinder.

Ques 1)

We know that the least amount of paper is required by the can whose lateral surface area is the smallest.

We know that the lateral surface area of cylinder is given by:

$LA=2\pi rh$

CAN               Radius             Height              Lateral Area

 A                   2 in.                 6 in.              75.36 square in.

 B                   2.5 in.              5 in.              78.5 square in.

 C                   3 in.                  4 in.               75.36 square in.  

 D                   3.2 in.               3 in.               60.288 square in.

Hence, the can that requires the least amount of paper is:

CAN D.

Ques 2)

r=6 in.

h=15 in.

The surface area of cylinder is calculated as:

$SA=2\pi r^2+2\pi rh$

Hence, on putting the given values in the formula we have:

$SA=2\pi\times 6^2+2\pi \times 6\times 15\\\\SA=252\pi\ in.^2$

Hence,

SA=252 pi in.^2.

Ques 3)

diameter(d)=8 cm.

This means that:

r=d/2=4 cm.

h=18 cm.

Hence, the volume(V) of the cylinder is calculated as:

$V=\pi r^2h\\\\V=\pi\times (4)^2\times 18\\\\V=288\pi\ cm^3$

Hence,

Volume is: 288 pi cm^3

Ques 4)

d=40 feet.

h=32 feet.

Hence, r=d/2=40/2=20 feet.

Hence, the surface area of the cylinder is calculated as:

$SA=2\pi r^2+2\pi rh\\\\SA=2\pi\times (20)^2+2\pi\times  20\times 32\\\\SA=2080\pi\ ft.^2$

Hence, SA=2080 pi ft. ^2

Ques 5)

r=6 in.

h=15 in.

Hence, the volume of the cylinder is given by:

$V=\pi r^2h\\\\V=\pi \times (6)^2\times 15\\\\V=540\pi\ in.^3$

Hence,

Volume= 540 pi in. ^3