Question

Which frequency would be the fourth harmonic in a series for a closed pipe resonator if the findamental is 256 hz?

Answer 1

The frequency of the nth-harmonic of a closed pipe resonator is given by
$f_n = n f_1$
where $f_1$ is the fundamental frequency.

For the pipe in our problem, the fundamental frequency is $f_1 = 256 Hz$, so the 4th harmonic (n=4) will be
$f_4 = 4 \cdot 256 Hz = 1024 Hz$

Answer 2

Answer:

1792 Hz

Explanation: