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What is the formula of the chromium(iii) complex that contains two ammonia and four thiocyanate (scn−) ligands?

Respuesta :

Answer is: formula of the complex is [Cr(NH₃)₂(SCN)₄].
This complex has negative charge (-1) because chromium (central atom or metal) has oxidation number +3, first ligand ammonia has neutral charge and second ligand thiocyanate has negative oxidation number -1:
+3 + 2
·0 + 4·(-1) = -1.
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