Question

Two polarizers are oriented at 68 ∘ to one another. unpolarized light falls on them. part a what fraction of the light intensity is transmitted?

Answer 1

Answer:

Fraction=0.0701

or

Fraction=7.01%

Explanation:

Apply Malus Law

I₁=I₀/2

I₂=I₁cos²θ

I₂=(I₀/2)cos²(68)

I₂=I₀(0.1403/2)

Fraction of light is given as

I₂/I₀=0.1403/2=0.0701

To get in %

Fraction=0.0701×100

Fraction=7.01%

Answer 2

The Fraction of light intensity transmitted is : 0.0701 ≈ 7.01%

Given data :

Two polarizers orientation = 68°

Determine the Fraction of light intensity transmitted

Applying  Malus Law which states that

 L₁ =  L₀ / 2 ------ ( 1 )

 L₂ = L₁cos²θ ----- ( 2 )

Rewrite equation ( 2 ) by inserting equation ( 1 )

L₂ = ( L₀ / 2 ) cos² (68°) ---- ( 3 )

Resolving equation ( 3 )

Therefore :  L₂ =  L₀ ( 0.1403 / 2 )

Final step : Determine the fraction of light intensity

L₂ / L₀ = ( 0.1403 / 2 )

          = 0.0701 ≈  7.01 %

Hence we can conclude that the Fraction of light intensity transmitted is : 0.0701 ≈ 7.01%

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