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To know how many moles of iron can be recovered from 100 kg of Fe₃O₄ we'll need to use the molar mass of Fe₃O₄ and apply the conversion factor to go from kg of Fe₃O₄ to moles of Fe in the following way:

[tex]100 kg Fe_3O_4* \frac{1000 g}{1 kg}* \frac{1 mol Fe_3O_4}{231,533 g Fe_3O_4}* \frac{3 mol Fe}{1 mol Fe_3O_4}=1192,68 moles Fe [/tex]

So, theoretically, one could recover 1192,68 moles of Fe from 100 kg of Fe₃O₄

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Answer:

1296 moles of Fe

Explanation:

To know how many iron can be recovered you need to know the moles of Fe₃O₄ in 100,0kg (100,0x10³g) using molar mass of Fe₃O₄ (231,533 g/mol):

Moles of Fe₃O₄:

100,0x10³g × (1mol / 231,533g) = 431,9 moles of Fe₃O₄

As molecular formula of Fe₃O₄ contains 3 atoms of Fe, you will have 3 moles of Fe per mole of Fe₃O₄. Thus, moles of Fe are:

431,9 moles of Fe₃O₄ × (3 moles Fe / 1 mole of Fe₃O₄) = 1296 moles of Fe

I hope it hepls!

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