Respuesta :
The amount of heat needed to raise the temperature of a substance by [tex]\Delta T[/tex] is given by
[tex]Q=m C_s \Delta T[/tex]
where
m is the mass of the substance
Cs is its specific heat capacity
[tex]\Delta T[/tex] is the increase in temperature
For oxygen, the specific heat capacity is approximately
[tex]C_s = 0.92 J/(g K)[/tex]
The variation of temperature for the sample in our problem is
[tex]\Delta T= -15^{\circ}C-(-30^{\circ} C)=+15^{\circ}C=15 K[/tex]
while the mass is m=150 g, so the amount of heat needed is
[tex]Q=m C_s \Delta T=(150 g)(0.92 J/g K)(15 K)=2070 J[/tex]
[tex]Q=m C_s \Delta T[/tex]
where
m is the mass of the substance
Cs is its specific heat capacity
[tex]\Delta T[/tex] is the increase in temperature
For oxygen, the specific heat capacity is approximately
[tex]C_s = 0.92 J/(g K)[/tex]
The variation of temperature for the sample in our problem is
[tex]\Delta T= -15^{\circ}C-(-30^{\circ} C)=+15^{\circ}C=15 K[/tex]
while the mass is m=150 g, so the amount of heat needed is
[tex]Q=m C_s \Delta T=(150 g)(0.92 J/g K)(15 K)=2070 J[/tex]
Answer:
2.1 kJ
Explanation:
The heat (q) required to raise the temperature of oxygen can be calculated using the following expression.
q = c × m × ΔT
where,
c: specific heat capacity (c(O₂): 0.913 J/g.°C)
m: mass
ΔT: change in the temperature
q = c × m × ΔT
q = (0.913 J/g.°C) × 150 g × [-15°C - (-30°C)] = 2.1 × 10³ J = 2.1 kJ