Respuesta :
CH3COOCH3
We have 2 atoms of oxygen - 2*M(O)=2*16.0=32.0 g/mol
Molar mass (CH3COOCH3)= 3*M(C)+2*M(O)+6*M(H)=3*12.0+2*16.0+6*1.0=
= 74.0 g/mol
% oxygen=(32.0 g/mol)/( 74.0 g/mol) *100% ≈ 43.2%
We have 2 atoms of oxygen - 2*M(O)=2*16.0=32.0 g/mol
Molar mass (CH3COOCH3)= 3*M(C)+2*M(O)+6*M(H)=3*12.0+2*16.0+6*1.0=
= 74.0 g/mol
% oxygen=(32.0 g/mol)/( 74.0 g/mol) *100% ≈ 43.2%
The percentage by mass is used to calculate the mass in the percentage of the element with respect to compound and molecule. The mass percent of oxygen in acetic acid is 43.2%.
What is mass percent?
Percentage by mass or mass percent is the method to determine the mass of an element in a compound in percentage form. The percentage by mass depends on the mass of the element and the molecule or the compound.
The mass percent is calculated by dividing the mass of the element by the molar mass of the compound followed by multiplying it by 100. It is calculated as,
Acetic acid has two oxygen atoms so, the mass of O₂ = 2 × 16.0
= 32.0 g/mol
The molar mass of acetic acid (CH₃COOCH₃):
= 3 × 12.0 + 2 × 16.0 + 6 × 1.0
= 74.0 g/mol
Mass percent oxygen = (32.0 g/mol / 74.0 g/mol) × 100%
= 43.2%
Therefore, 43.2% is the mass percent of oxygen in acetic acid.
Learn more about mass percent here:
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