Question

A 1.5 v battery moves 9000 c of charge around a circuit. part a by how much does the chemical energy of the battery decrease

Answer 1

potential difference is energy per coloumb of charge so energy = vq

energy  =  1.5    *    9000    =   13500 J

Answer 2

In moving a charge through potential difference, work done can be calculated as follows:

$W=-q\times V$

Here, q is charge and V is potential difference.

(a) According to law of conservation of energy, chemical energy of the battery will be equal to work done, thus,

$E=-q\times V$

Putting the values,

$E=-(9000 C)\times (1.5 V)=-13500 CV$

Since, 1J=CV

Thus, the amount of chemical energy decreases will be 13500 J.