Each year Luke earns the amount earned the previous year multiplied by 1.10 (which corresponds to a 10% raise).
The total earnings will be the sum of each year earnings.
This sum is given by the geometric series formula:
[tex] S_{n} = \frac{ a_{1}(1 - r^{n}) }{1 - r} [/tex]
where:
a₁ = first term of the series
r = common ratio
n = number of term wanted
Therefore, the total earnings will be:
[tex] S_{n} = \frac{ 36000(1 - 1.10^{5}) }{1 - 1.10} [/tex]
= 219783.60$
During the first five years of the job Luke earned 219783.60$.