Ideal Gas equation will be used assuming all the gases are acting Ideally,
P V = n R T
Solving for V,
V = n R T / P ----- (1)
Standard Temperature = 273 K
Standart Pressure = 1 atm
Gas Constant R = 0.08206 atm.L.mol⁻¹.K⁻¹
1) For 1.7 mole of H₂;
Putting values in eq.1,
V = (1.7 mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm
V = 38.08 L
2) For 1.8 ×10⁻² mole of N₂;
Putting values in eq.1,
V = (1.8 ×10⁻² mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm
V = 0.403 L
3) For 2.5 ×10² mole of O₂;
Putting values in eq.1,
V = (2.5 ×10² mol × 0.08206 atm.L.mol⁻¹.K⁻¹ × 273 K) ÷ 1 atm
V = 5600 L
