Question

A series circuit contains a 30 Ω resistor, a 20 Ω resistor, and a 10 Ω resistor. The power supply provides 100 V to the circuit.

The current in the 10 Ω resistor, to two significant figures, is
A.

Answer 1

The correct answer is 1.7 Amps.    

Answer 2

Answer:

The current in the 10 ohm resistance is 1.67 A.

Explanation:

Given that,

Voltage v = 100 V

A series circuit contains a 30 Ω resistor, a 20 Ω resistor, and a 10 Ω resistor.

$R =R_{1}+R_{2}+R_{3}$

$R = 30+20+10$

$R= 60\ ohm$

Using Ohm's law

The voltage of the circuit is the product of the current and resistance.

$V = I\times R$

$I =\dfrac{V}{R}$

$I = \dfrac{100}{60}$

$I = 1.67\ A$

The current will be same in all resistance because all resistance in series.

Hence, The current in the 10 ohm resistance is 1.67 A.