Question

A sample of gas occupies a volume of 445 mL at a temperature of 274 K. At what temperature will this sample of gas occupy a volume of 499 mL? Show all of the work used to solve this problem.

Answer 1

The   temperature  that    the  sample  of    gas  occupy   a  volume    of  499ml  is  calculated  using  Charles  law  formula
that  is  V1/T1  = V2/T2
V1=  445 ml
T1=  274  k
V2 =  499 ml
T2=  ?

from equation  above  T2  =  T1V2/ V1
=  274 k  x 499 ml/445ml  =  307.25  k

Answer 2

Answer : The final temperature of gas will be, 307.25 K

Explanation :

Charles' Law : It is defined as the volume of gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

$V\propto T$

or,

$\frac{V_1}{V_2}=\frac{T_1}{T_2}$

where,

$V_1$ = initial volume of gas = 445 ml

$V_2$ = final volume of gas = 499 ml

$T_1$ = initial temperature of gas = 274 K

$T_2$ = final temperature of gas = ?

Now put all the given values in the above formula, we get the final temperature of the gas.

$\frac{445ml}{499ml}=\frac{274K}{T_2}$

$T_2=307.25K$

Therefore, the final temperature of gas will be, 307.25 K