we know that
perimeter rectangle A=2*[5+3]-----> 16 in
let
x------> length side rectangle B
y-------> width side rectangle B
so
x=6+y-------> equation 1
16=2[x+y]------> equation 2
I substitute 1 in 2
16=2*[6+y+y]-------> 16=2*[6+2y]-----> 16=12+4y-----> 4y=16-12
y=4/4--------> y=1 in
x=6+1---->x=7 in
the answer is
the dimensions of rectangle B are
length side is 7 in
width side is 1 in