[tex]\bf \textit{volume of a pyramid}\\\\ V=\cfrac{1}{3}Bh~~ \begin{cases} B=area~of\\ \qquad its~base\\ h=height\\ \cline{1-1} V=160 \end{cases}\implies 160=\cfrac{Bh}{3}\implies 480=Bh \\\\[-0.35em] ~\dotfill\\\\ \begin{cases} 480=&2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 3\cdot 5\\ &8\cdot 60\\ &32\cdot 15 \end{cases}~\hspace{5em}\stackrel{B}{8}\times\stackrel{h}{60}\qquad \qquad \stackrel{B}{32}\times\stackrel{h}{15}[/tex]
