Question

Bug zapper #1 zapped a fair number of bugs, but Zapper #2 zapped 22 more. Zapper #3 zapped 45 more bugs than #2 did. If all three zappers zapped 398 bugs in total, how many were zapped by #1 alone?

Answer 1

Bug zapper #1 zapped 103 bugs
103 + 22 = 125
125 + 45 = 170
103 + 125 + 170 = 398

Answer 2

The number of bugs zapped by the zapper #1 is 103 such that the number of bugs zapped by the zapper #2 is 22 more than that of zapper #1 and the number of bugs zapped by the zapper #3 is 45 more than that of zapper #2 and the total number of bugs zapped is 398.

Linear Equations

A linear equation with one variable is one in which only one variable is present. Mathematically, $y=mx+c$ is a general form of a linear equation.

We need to first draft a linear equation for the total number of bugs zapped by three zappers and then, solve it to get to the final result.

How to solve the linear equations?

Let bug zapper #1 zapped $x$ numbers of bugs.

So, according to the question, the number of bugs zapped by the zapper #2 is $x+22$.

Similarly, the number of bugs zapped by the zapper #3 will be $(x+22+45)=x+67$.

The total number of bugs zapped is 398. So, we can write the linear equation as-

$x+(x+22)+(x+67)=398$

Now, solve the above linear equation-

$3x+89=398\\x=\dfrac{398-89}{3}\\x=103$

Thus, the number of bugs zapped by the zapper #1 is 103.

Learn more about the linear equations here- https://brainly.com/question/11897796

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