Hello!
The dissociation reaction of HCl is the following:
HCl(aq) + H₂O(l) → H₃O⁺(aq) + Cl⁻(aq)
The concentration of H₃O⁺ is the same concentration as HCl (0,0035 M). Now, we calculate the pH using the following equation:
[tex]pH=-log(H_3O^{+})=-log(0,0035 M)= 2,46[/tex]
Now, we determine the pOH using the following equation:
[tex]pOH=14-pH=14-2,46=11,54[/tex]
To finish, we apply the definition of pOH and clear for [OH⁻]:
[tex][OH]= 10^{-pOH}= 10^{-11,54}=2,88*10^{-12} M[/tex]
So, [OH⁻]=2,88*10⁻¹²
Have a nice day!
