The Pythagoras' Theorem in mathematics defines a relation between the three sides of a right-triangle. It states that the square of larger side of the triangle(hypotenuse) is equals to the sum of square of its other two sides(base and perpendicular).
It can be written as:
[tex]\rm Hypotenuse^2 = Base^2 + Perpendicular^2[/tex]
On solving the given question, the correct statements obtained are:
- The radius of circle O is 13
- LP is a diameter of circle O.
- ∠[tex]\rm LMP[/tex] intercepts a semicircle.
To reach the above conclusions, following calculation is required:
The largest side of the Δ[tex]\rm PML[/tex] is [tex]\RM PL[/tex]
Therefore,
[tex]\begin{aligned} \rm PL^2 &= MP^2 + ML^2\\PL^2 &= 10^2 + 24^2\\PL^2 &= 100 + 576\\PL^2 &= 676\\PL &= \sqrt{676} \\PL &= 26\end[/tex]
Since, PL passes through the center of the circle, it is the diameter of the given circle.
Radius of the circle is half the diameter.
Hence radius of circle O will be [tex]\dfrac{26}{2} = 13[/tex].
Also diameter divides the circle into two semi-circles. Therefore the intercepting point of ∠[tex]\rm LMP[/tex] is a semi-circle.
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