Line segments MP and ML are perpendicular chords in circle O. MP = 10 and ML = 24.

Which statements about circle O are true? Check all that apply.

-The radius of circle O is 13.
-The diameter of circle O is 34.
-LP is a diameter of circle O.
-∠LMP intercepts a semicircle.
-The measure of arc LP is 90°.

Line segments MP and ML are perpendicular chords in circle O MP 10 and ML 24 Which statements about circle O are true Check all that apply The radius of circle class=

Respuesta :

The diameter of this circle at the same time hypotenuse of triangle LMP
|LM|²=24²+10²
|LM|=√(676)=26 - diameter
so radius =26/3=13
-The radius of circle O is 13.
-LP is a diameter of circle O.
-∠LMP intercepts a semicircle.

The Pythagoras' Theorem in mathematics defines a relation between the three sides of a right-triangle. It states that the square of larger side of the triangle(hypotenuse)  is equals to the sum of square of its other two sides(base and perpendicular).

It can be written as:

[tex]\rm Hypotenuse^2 = Base^2 + Perpendicular^2[/tex]

On solving the given question, the correct statements obtained are:

- The radius of circle O is 13

- LP is a diameter of circle O.

- ∠[tex]\rm LMP[/tex] intercepts a semicircle.

To reach the above conclusions, following calculation is required:

The largest side of the Δ[tex]\rm PML[/tex] is [tex]\RM PL[/tex]

Therefore,

[tex]\begin{aligned} \rm PL^2 &= MP^2 + ML^2\\PL^2 &= 10^2 + 24^2\\PL^2 &= 100 + 576\\PL^2 &= 676\\PL &= \sqrt{676} \\PL &= 26\end[/tex]

Since, PL passes through the center of the circle, it is the diameter of the given circle.

Radius of the circle is half the diameter.

Hence radius of circle O will be [tex]\dfrac{26}{2} = 13[/tex].

Also diameter divides the circle into two semi-circles. Therefore the intercepting point of ∠[tex]\rm LMP[/tex] is a semi-circle.

Learn more about  Pythagoras' Theorem here:

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