The minimum value of the quadratic function is y = -4.
How to get the minimum value of a quadratic function?
If a quadratic function:
y = a*x^2 + b*x + c
has a > 0, then the function has a minimum at the vertex.
Remember that for the general quadratic function the x-value of the vertex is:
x = -b/2a
In this case, we have:
h(x) = x^2 - 16x + 60
So the x-value of the vertex is:
x = -(-16)/(2*1) = 8
Evaluating the function in x = 8 we get:
h(8) = 8^2 - 16*8 + 60 = -4
That is the minimum of the function.
If you want to learn more about quadratic functions, you can read:
https://brainly.com/question/1214333
