Respuesta :

So, the ball goes 3.2653 meters high. Hope it helps

Answer:

22.62 m

Step-by-step explanation:

Angle of projection, θ = 30°

initial velocity, u = 16 m/s

Let it goes upto the distance of R.

Use the formula for the horizontal range.

[tex]R=\frac{u^{2}Sin2\theta }{g}[/tex]

where, g be the acceleration due to gravity

[tex]R=\frac{16^{2}Sin60 }{9.8}[/tex]

R = 22.62 m Thus, the ball goes upto a distance of 22.62 m.

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