Answer:
22.62 m
Step-by-step explanation:
Angle of projection, θ = 30°
initial velocity, u = 16 m/s
Let it goes upto the distance of R.
Use the formula for the horizontal range.
[tex]R=\frac{u^{2}Sin2\theta }{g}[/tex]
where, g be the acceleration due to gravity
[tex]R=\frac{16^{2}Sin60 }{9.8}[/tex]
R = 22.62 m Thus, the ball goes upto a distance of 22.62 m.