Respuesta :
De Broglie's identity gives the relationship between the momentum and the wavelength of a particle:
[tex]p=mv= \frac{h}{\lambda} [/tex]
where
p is the particle momentum
m is its mass
v its velocity
h is the Planck constant
[tex]\lambda[/tex] is the wavelength
By re-arranging the equation, we get
[tex]\lambda= \frac{h}{mv} [/tex]
and by using the data about the proton, given in the text, we can find the proton's wavelength:
[tex]\lambda= \frac{h}{mv} = \frac{6.63 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.00 \cdot 10^6 m/s)} =7.99 \cdot 10^{-14} m[/tex]
[tex]p=mv= \frac{h}{\lambda} [/tex]
where
p is the particle momentum
m is its mass
v its velocity
h is the Planck constant
[tex]\lambda[/tex] is the wavelength
By re-arranging the equation, we get
[tex]\lambda= \frac{h}{mv} [/tex]
and by using the data about the proton, given in the text, we can find the proton's wavelength:
[tex]\lambda= \frac{h}{mv} = \frac{6.63 \cdot 10^{-34} Js}{(1.66 \cdot 10^{-27} kg)(5.00 \cdot 10^6 m/s)} =7.99 \cdot 10^{-14} m[/tex]