Question

.35 grams of sodium chloride are dissolved to make 150 milliliters of solution. What is the molarity of the solution?

Answer 1

NaCl molar mass 58.4 g/mol

moles of NaCl = .35 g * 1 mol/58.4 g = 0.005993 mol
volume of solution = 150 mL = 0.15 L

molarity = mol/vol(in L)
[NaCl] = 0.005933mol/0.15L = 0.03995 M = 0.040 M