Methanol reacts with oxygen as follow,
CH₃OH + 3/2 O₂ → CO₂ + 2 H₂O
Data Given;
Volume of Methanol = 60 mL
Density of Methanol = 0.787 g/mL
Calculating mass of Methanol as;
Mass = Density × Volume
Mass = 0.787 g/mL × 60 mL
Mass = 47.22 g
According to equation,
32 g of Methanol requires = 48 g (3/2 moles) of O₂
So,
47.22 g of Methanol will require = X g of O₂
Solving for X,
X = (47.22 g × 48 g) ÷ 32 g
X = 70.83 g of O₂
