A) 0.1211
B) 0.3889
C) 0.9782
Explanation:
A) We use a binomial distribution for this:
[tex]_nC_r(p)^r(1-p)^{n-r}
\\
\\_{12}C_3(0.42)^3(1-0.42)^{12-3}=_{12}C_3(0.42)^3(0.58)^9=0.1211[/tex]
B) Using a graphing calculator, we find the sum of the binomial probabilities from 0 up to (not including) 5: 0.6111. Now subtract this from 1, since we want everything greater than or equal to 4: 1 - 0.6111 = 0.3889
C) Using a graphing calculator, we find the sum of the binomial probabilities from 0 up to (not including) 8: 0.9782