Question

The length of a rectangle is 5/2 units greater than twice its width. If its width is w, which expression gives the perimeter of the rectangle in terms of w? A. 2(5/2 w) + w B. 5/2 w + w C. 3 w + 10/2 D. 6 w + 5

Answer 1

Width = w
Length = 2w + 5/2

Perimeter = 2(Length + Width)
Perimeter = 2( w + 2w + 5/2)
Perimeter = 2(3w + 5/2)
Perimeter = 6w + 5

-----------------------------------------------------
Answer: The perimeter is 6w + 5 (Answer D)
-----------------------------------------------------

Answer 2

Answer:

D. 6 w + 5

Step-by-step explanation:

In order to solve this you first have to express the length and width of the rectangle in terms of W:

Width= W

Length= 5/2 units more than twice its width= 2w + 5/2

No we just have to add that up in an equation, using the formula for perimeter:

$Perimeter= 2(width) + 2(length)\\Perimeter=2w+ 2(2w + \frac{5}{2})\\Perimeter= 2w+4w+5\\Perimeter= 6w +5$

SO we know that the perimeter expressed in terms of w is equal to 6w +5 units.