Question

What function is represented below?

graph begins in the second quadrant and decreases quickly while crossing the ordered pair 0, negative 1. When the graph enters the fourth quadrant, it begins to decrease slowly as it approaches the line y equals negative 2.

f(x) = one fourth to the power of x plus 2
f(x) = one fourth to the power of x + 2
f(x) = one fourth to the power of x minus 2
f(x) = one fourth to the power of x − 2

Answer 1

Answer:

f(x)=$\frac{1}{4} ^{x} -2$

Step-by-step explanation:

The given function is an exponential function .All the graphs will begin from second quadrant .  The exponential graph crosses the ordered pair at (0,-1)

It then decreases slowly as it approaches y=-2.

The point (0,-1) lies on the graph:

$y=\frac{1}{4} ^{x} -2$

Answer 2

The function that is represented in the graph is:

$f(x) = (1/4)^x - 2$

Which function represents the graph?

We know that it passes the point (0, -1), and tends asymptotically to y = -2.

So, the constant term must be equal to -2, then the only option with this is:

$f(x) = (1/4)^x - 2$

Notice that:

$f(0) = (1/4)^0 - 2 = -1$

And when x tends to infinity, the first term becomes zero, so the function tends to negative 2.

If you want to learn more about graphs:

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