Kelly hiked in the woods it took her 1/14 hour to walk 1/4 mile after she snacked she walked another 1/6 mile in 1/16 hour

Choose true or false for each statement

Kelly hiked in the woods it took her 114 hour to walk 14 mile after she snacked she walked another 16 mile in 116 hour Choose true or false for each statement class=

Respuesta :

dtegan
My best answer would be False,True, False, False

General Idea:

The relationship between rate(R), distance(D) and time(T) given below:

[tex] R= \frac{D}{T}  [/tex]

Applying the concept:

We need to make use of the formula to find Kelly's walking rate before and after her snack

[tex] Kelly \; Walking \; Rate \; before \; Snack:\\Distance \div Time = \frac{1}{4}  \div \frac{1}{14}  =  \frac{1}{4}  \times \frac{14}{1}  = \frac{14}{4}  = \frac{7}{2}  =  3 \frac{1}{2} \;   miles \; per \; hour\\\\Kelly \; Walking \; Rate \; after \; Snack:\\Distance \div Time = \frac{1}{6}  \div \frac{1}{16}  =  \frac{1}{6}  \times \frac{16}{1}  = \frac{16}{6}  = \frac{8}{3}  =  2 \frac{2}{3} \;   miles \; per \; hour\\\\ [/tex]

Option A isn't correct because before snack Kelly walking rate is not 4/14 miles per hour.

Option B is Correct, Kelly walking rate after snack is 2 2/3 miles per hour.

Option C isn't correct because it doesn't took Kelly 2 hours longer to walk 1/6 mile than it did for her to walk 1/4 mile.  It took 1/112 hour longer.

[tex]  \frac{1}{14}  - \frac{1}{16}  = \frac{1 \cdot 8}{14 \cdot 8}  - \frac{1 \cdot 7}{16 \cdot 7}  =  \frac{8}{112} - \frac{7}{112}  = \frac{1}{112}     [/tex]

Option D isn't correct because 2 2/3 miles per hour is slower than 3 1/2 miles per hour.

Conclusion:

Option B is Correct, Kelly walking rate after snack is 2 2/3 miles per hour.

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