Respuesta :

[tex]\bf \textit{arc's length}\\\\ s=\cfrac{\theta \pi r}{180}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=16\\ \theta =140 \end{cases}\implies s=\cfrac{(140)\pi (16)}{180} \\\\\\ \textit{area of a sector of a circle}\\\\ A=\cfrac{\theta \pi r^2}{360}~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad degrees\\ ------\\ r=16\\ \theta =140 \end{cases}\implies A=\cfrac{(140)\pi (16)^2}{360}[/tex]
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