Reaction equation : HBr + KOH → KBr + H₂O 1 mole of HBr reacts with 1 mole of KOH. So, mole ratio between them is 1:1 mmol of HBr = 56.0 ml x 0.25 M = 14 mmol mmol of KOH = 28.0 ml x 0.50 M = 14 mmol So after the mixing neither HBr nor KOH remains and the solution contains only KBr and water which are both neutral so the pH of the solution will be 7.0
