Respuesta :
First, we can start by expanding (a+b)²
a²+2ab+b²
We can then use the commutative property to separate this into:
a²+b² + 2ab
Since we are given the values for a²+b² and ab, we can plug in these values into the equation:
16 + (2)(8)
16+16
32
Therefore, the value of (a+b)² is 32
a²+2ab+b²
We can then use the commutative property to separate this into:
a²+b² + 2ab
Since we are given the values for a²+b² and ab, we can plug in these values into the equation:
16 + (2)(8)
16+16
32
Therefore, the value of (a+b)² is 32
(a + b)^2 = a^2 + 2ab + b^2
Given
ab = 8
a^2 + b^s = 16
Substitute and solve
a^2 + 2ab + b^2
a^2 + b^2 = 16
ab = 8
2ab = 16
Therefore a^2 + 2ab + b^2 = 32 <<<< answer
Given
ab = 8
a^2 + b^s = 16
Substitute and solve
a^2 + 2ab + b^2
a^2 + b^2 = 16
ab = 8
2ab = 16
Therefore a^2 + 2ab + b^2 = 32 <<<< answer