Question

Q is equidistant from the sides of TSR. Find the value of x. The diagram is not to scale.
A. 3
B. 23
C. 20
D. 11

Answer 1

$2x + 17 = 23$
$2x = 6$
$x = 3$

The answer is A! Hope this helps! :)

Answer 2

ANSWER

$x = 3$

EXPLANATION

Since the ray through Q is equidistant from, TSR, it bisects angle TSR.

This implies that, the $23\degree$ angle is equal to the $(2x + 17) \degree$ angle. We therefore write the following equation that can help us find the value of x.

$(2x + 17) \degree=23 \degree$

We group like terms to get,

$2x=23\degree- 17\degree$

This gives us,

$2x=6$

We divide both sides by 3 to get,

$x=\frac{6}{2}$

$\therefore\:x=3$

The correct answer is A.