Answer with Step-by-step explanation:
As we can see from the graph the line passes through (-5,-1)
Hence, the equation must satisfy that when x= -5,y= -1
A. y = 3/2x - 13/3
Putting x= -5
[tex]y=\dfrac{3}{2}\times (-5)-\dfrac{13}{3}\\ \\y=-\dfrac{15}{2}-\dfrac{13}{3}\\ \\y=-\dfrac{71}{6}[/tex]
y≠ -1
B. y = 2/3x - 13/3
Putting x= -5
[tex]y=\dfrac{2}{3}\times (-5)-\dfrac{13}{3}\\ \\y=-\dfrac{10}{3}-\dfrac{13}{3}\\ \\y=-\dfrac{23}{3}[/tex]
y≠ -1
C. y = -2/3x - 13/3
Putting x= -5
[tex]y=-\dfrac{2}{3}\times (-5)-\dfrac{13}{3}\\ \\y=\dfrac{10}{3}-\dfrac{13}{3}\\ \\y=-\dfrac{3}{3}[/tex]
y= -1
Hence, The equation of the following line written in slope-intercept form is:
C. y = -2/3x - 13/3