Angle A=11x-4, Angle B = 4x-11, and Angle C=63-4x. List the sides of triangle ABC in order from shortest to longest.
A. AB, AC, BC
B. AC, AB, BC
C. BC, AB, AC
D. AB, BC, AC

Respuesta :

1. The sum of of the interior angles of a triangle is 180°.

 2. Keeping this on mind, you have:

 A+B+C=180

 A=11x-4
 B = 4x-11
 C=63-4x

 3. When you substitute these values, you obtain:

 A+B+C=180
 11x-4+4x-11+63-4x=180
 11x+48=180
 11x=180-48
 11x=132
 x=132/11
 x=12

 3. Therefore:

 A=11(12)-4
 A=128°

 B = 4(12)-11
 B=37°

 C=63-4(12)
 C=15°

 5. The answer is:

 A. AB, AC, BC
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