Question

what are the coordinates of the vertex of the function below?write your answer in the form (x,y).
y+9=-6(x-2)^2

Answer 1

The equation in standard form is y - k = a(x - h)², so the vertex takes the place of (h, k), and we get (2, -9).
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Hope this helps!

Answer 2

Answer:

vertex is (2,-9)

Step-by-step explanation:

$y+9=-6(x-2)^2$

The general vertex form of quadratic equation is

$y=a(x-h)^2+k$

Where (h,k) is the vertex

First we solve the given equation for y. then compare the given equation with the general equation.

$y+9=-6(x-2)^2$

Subtract 9 from both sides

$y=-6(x-2)^2-9$

The value of h=2  and the value of k = -9

So vertex is (2,-9)