Respuesta :
We need to find an equation for each situation. Let x be the number of GB of data used.
Statement 1: At Noise Pollution Cellular, plan A is $30.00 per month and $5.00 for every gigabyte of data used.
Plan A cost equation [tex] C(x) = 30 + 5x [/tex]
Statement 2: At Noise Pollution Cellular, Plan B is $50.00 per month and $2.00 for every gigabyte of data used.
Plan B cost equation [tex] C(x) = 50 + 2x [/tex]
Number of GB of data for which both the plan A and plan B cost are same.
[tex] 30+5x=50+2x \\ Subtracting \; 2x \; \& \;30\; on\; both\; sides\; \\ \\30+5x-2x-30=50-30+2x-2x \\Combining \; like \; terms\\\\3x=20\\Dividing \; like \; terms\\\\ \frac{3x}{3}=\frac{20}{3} \\ \\x=6\frac{2}{3} [/tex]
When
[tex] x=6 \\\\ Plan \; A \; Cost = 30+5(6)=30+30=\$60\\ Plan \; B \; Cost = 50+2(6)=50+12= \$72\\ \\ From \; 5\leq x\leq 6\frac{2}{3} , \; Plan \; A \; is \; Cheaper! [/tex]
When
[tex] x = 7\\\\ Plan \; A \; Cost= 30 + 5(7) =30+35 = \$65\\\\Plan \; B \; Cost = 50 + 2(7)=50+14=\$64 \\ \\ From \; 6\frac{2}{3} \leq x \leq 8, \; Plan\; B \; is \; Cheaper ! [/tex]