Question

Approximate the change in the volume of a right circular cylinder of fixed radius requals21 cm when its height decreases from hequals12 cm to hequals11.9 cm ​(upper v left parenthesis h right parenthesis equals pi r squared h​).

Answer 1

The volume of the cylinder is given by:
 V = pi * r ^ 2 * h
 For h = 12cm:
 V1 = pi * ((21) ^ 2) * (12)
 V1 = 16625.30832 cm ^ 3
 For h = 11.9cm:
 V2 = pi * ((21) ^ 2) * (11.9)
 V2 = 16486.76409 cm ^ 3
 The change in volume is given by:
 V1-V2 = 16625.30832-16486.76409
 V1-V2 = 138.54423 cm ^ 3
 Answer:
 the change in the volume is:
 V1-V2 = 138.54423 cm ^ 3

Answer 2

Using the formula for the volume of a cylinder, it is found that it decreases from 16625 cm³ to 16487 cm³, which is a change of 138 cm³.

The volume of a cylinder of radius r and height h is given by:

$V = \pi r^2h$

In this problem, the radius is of 21 cm, thus $r = 21$.

With a height of 12 cm, that is, $h = 12$, the volume, in cubic centimetres, is given by:

$V = \pi (21)^2(12) = 16625$

With a height of 11.9 cm, that is, $h = 11.9$, the volume, in cubic centimetres, is given by:

$V = \pi (21)^2(11.9) = 16487$

The volume decreases from 16625 cm³ to 16487 cm³.

The change is of:

$16625 - 16487 = 138$

A similar problem is given at https://brainly.com/question/22789697