Answer:
[tex]10\ bugs[/tex]
Step-by-step explanation:
Let
x----> the number of bugs that the spider ate this month
y----> the number of bugs that the spider ate last month
we know that
[tex]100\%+25\%=125\%=125/100=1.25[/tex]
so
we have
[tex]y=8\ bugs[/tex]
The linear equation that represent this situation is
[tex]x=1.25(y)[/tex]
substitute the value of y
[tex]x=1.25(8)=10\ bugs[/tex]