All you have to do is plug in the given values into the given equation and evaluate.
The expression is,
[tex]A(t) = l{e}^{rt} [/tex]
But we have to analyze the problem carefully. This is a natural phenomenon that can be modelled by a decay function. The reason is that, after every hour we expect the medicine in the blood to keep reducing.
Therefore we use the decay function rather. This is given by,
[tex]A(t) = l{e}^{-rt}[/tex]
where,
[tex]l = 100 \: milligrams[/tex]
[tex]r = \frac{14}{100} = 0.14[/tex]
and
[tex]t = 10 \: hours[/tex]
On substitution, we obtain;
[tex]A(10) = 100 \times {e}^{ - 0.14 \times 10} [/tex]
[tex]A(10) = 100 \times {e}^{ - 1.4} [/tex]
Now, we take our calculators and look for the constant
[tex]e[/tex]
,then type e raised to exponent of -1.4. If you are using a scientific or programmable calculator you will find this constant as a secondary function. Remember it is the base of the Natural logarithm.
If everything goes well, you should obtain;
[tex]A(10) = 100 \times 0.24659639[/tex]
This implies that,
[tex]A(10) = 24.66[/tex]
Therefore after 10 hours 24.66 mg of the medicine will still remain in the system.