Aloha!
We can Find Perimeter by Distance Formula:
AB = √[ (1 – 2)^2 + (3 - (-3) )^2 ] = √[ (-1)^2 + (6)^2 ] = √[ 1 + 36 ] = √(37) units
BC = √[ (2 - (-1) )^2 + (-3 - (-1))^2 ] = √[ (3)^2 + (-2)^2 ] = √[ 9 + 4 ] = √(13) units
AC = √[ (-1 – 1)^2 + (-1 – 3)^2 ] = √[ (-2)^2 + (-4)^2 ] = √[ 4 + 16 ] = √(20) units
Perimeter of Triangle ABC = AB +BC +AC
AB +BC +AC = √(37) + √(13) + √(20) units
Therefore, the perimeter of this triangle will be √(37) + √(13) + √(20) units
I hope this helps!
Adios!:)
