Respuesta :
Answer:
(D)
Step-by-step explanation:
From the figure, we have
The coordinates of the point F are: (-4,1).
The coordinates of the point G are: (0,-2)
The coordinates of the point J are: (0,4) and
The coordinates of the point H are: (-4,-2).
Now, the slope of the line FG is :
[tex]S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]S=\frac{-2-1}{0+4}[/tex]
[tex]S=\frac{-3}{4}[/tex]
And, the slope of the line HJ is:
[tex]S=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
[tex]S=\frac{-2-4}{-4-0}[/tex]
[tex]S=\frac{3}{2}[/tex]
Now, [tex]the slope of FG=\frac{1}{slope of HJ}[/tex]
[tex]\frac{-3}{4}=\frac{2}{3}[/tex]
which is not possible, thus They are not perpendicular because their slopes are not negative reciprocals.
Answer:
D.
They are not perpendicular because their slopes are not negative reciprocals.
Step-by-step explanation:
I got it correct on edge.
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