Find the separate areas.
We have a triangle with base 5 cm and height 5 cm, calculate the area:
[tex]\sf A=\dfrac{1}{2}bh[/tex]
Plug in what we know:
[tex]\sf A=\dfrac{1}{2}(5)(5)[/tex]
Multiply:
[tex]\sf A=12.5~cm^2[/tex]
Now for the two quarter circles, we know that if we put these two together we will end up with a semi-circle with radius 5 cm. The formula for the area of a circle is:
[tex]\sf A=\pi r^2[/tex]
A semi-circle is half of a whole circle, so the formula for the area of it must be:
[tex]\sf A=\dfrac{1}{2}\pi r^2[/tex]
Now plug in what we know(use 3.14 to approximate for pi):
[tex]\sf A\approx\dfrac{1}{2}(3.14)(5)^2[/tex]
Simplify the exponent:
[tex]\sf A\approx\dfrac{1}{2}(3.14)(25)[/tex]
Multiply:
[tex]\sf A\approx 39.25~cm^2[/tex]
Now add this to the area of the triangle to find the approximate area of the entire figure(round to the nearest tenth):
[tex]\sf 39.25+12.5=\boxed{\sf 51.8~cm^2}[/tex]