Respuesta :

[tex]\bf \textit{Pythagorean Identities} \\\\ 1+tan^2(\theta)=sec^2(\theta)\\\\ -------------------------------\\\\ 1+sec^2(x)sin^2(x)=sec^2(x) \\\\\\ 1+\cfrac{1}{cos^2(x)}\cdot sin^2(x)\implies 1+\cfrac{sin^2(x)}{cos^2(x)}\\\\\\ 1+tan^2(x)\implies sec^2(x)[/tex]
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