Respuesta :
There are two solutions for this problem because there are two solutions for all quadratics.
However, in this case, since the value of the discriminate (b^2 - 4ac) is negative, each of the answers are imaginary. So while there are two answers, there are no real answers to the above equation.
However, in this case, since the value of the discriminate (b^2 - 4ac) is negative, each of the answers are imaginary. So while there are two answers, there are no real answers to the above equation.
Answer:
The given equation [tex]3x^2+4x+2=0[/tex] has exactly 2 solutions.
Step-by-step explanation:
Given : Equation [tex]3x^2+4x+2=0[/tex]
We have to find the number of solutions of the given equation [tex]3x^2+4x+2=0[/tex]
Consider the given equation [tex]3x^2+4x+2=0[/tex]
Since, The highest degree of the given polynomial is 2.
For a polynomial, the highest degree gives the number of solution of that polynomial.
So, [tex]3x^2+4x+2=0[/tex] has 2 solutions.
The given equation [tex]3x^2+4x+2=0[/tex] has exactly 2 solutions.
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