Respuesta :

There are two solutions for this problem because there are two solutions for all quadratics.

However, in this case, since the value of the discriminate (b^2 - 4ac) is negative, each of the answers are imaginary. So while there are two answers, there are no real answers to the above equation.

Answer:

The given equation [tex]3x^2+4x+2=0[/tex] has exactly 2 solutions.

Step-by-step explanation:

Given :  Equation [tex]3x^2+4x+2=0[/tex]

We have to find the number of solutions of the given equation [tex]3x^2+4x+2=0[/tex]

Consider the given equation [tex]3x^2+4x+2=0[/tex]

Since, The highest degree of the given polynomial is 2.

For a polynomial, the highest degree gives the number of solution of that polynomial.

So, [tex]3x^2+4x+2=0[/tex] has 2 solutions.

The given equation [tex]3x^2+4x+2=0[/tex] has exactly 2 solutions.

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