Lets get started :)
8x - 9y + 2 = 0
9y = 8x + 2
y = [tex] \frac{8}{9}x + \frac{2}{9} [/tex]
Since the equation of this line is parallel to the one to be found, both have the same slopes: [tex] \frac{8}{9} [/tex]
Coordinates : ( - 7 , - 9 )
y - ( -9 ) = [tex] \frac{8}{9} [/tex] ( x - ( -7 ) )
y + 9 = [tex] \frac{8}{9}x + \frac{56}{9} [/tex]
y = [tex] \frac{8}{9}x + \frac{56}{9} - 9 [/tex]
y = [tex] \frac{8}{9}x - \frac{25}{9} [/tex]
