Respuesta :

Given are three married couples.

So, let us assume there are 3 men and 3 women

They are sitting in a row of 6 empty seats

There is a definite order constraint that each woman will sit left to her husband. The first woman gets 3 options to choose from 3 available seats. The second woman has two options left as already one seat is filled by the first woman. The last woman has one option left. So, it is [tex]3*2*1[/tex]

So, number of ways is 3! = [tex]3*2*1[/tex] = 6 ways.

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