Question

Mr. Tortelli left at 8:00
a.m. and is traveling 50 miles per hour. Mrs. Hart left at 9:00
a.m. and is traveling at 60 miles per hour. If Mr. Tortelli and Mrs. Hart are traveling the same direction, what time will it be when Mrs. Hart is at the same location as Mr. Tortelli?

Answer 1

Mr Tortelli has a headstart of 1 hour. He woud have covered 50 miles in that hour before Mrs Hart head off.

Let the number of hours needed after 9am for them to have traveled the same distance be x.

50 + 50x = 60x
10x = 50
x = 5

It will be 5 hours after 9am that they will meet at the same location. 

5 hours after 9am will be 2pm.

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Answer: Mr Tortelli and Mrs Hart will mee at 2pm.
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Answer 2

They will meet at 2 p.m..

Speed, distance, and Time

We know that sped, distance, and time all are in a relationship to each other. this relationship can be given as,

$\rm{Speed = \dfrac{Distance}{Time}$

 

Given to us

• Mr. Tortelli left at 8:00 a.m. and is traveling 50 miles per hour.
• Mrs. Hart left at 9:00  a.m. and is traveling at 60 miles per hour.
• If Mr. Tortelli and Mrs. Hart are traveling in the same direction,

Assumption

Let the time at which they both meet be x from the starting point.

Time Calculation

The time taken by Mr. Tortelli to reach to destination is,

$\rm{Distance}={speed\times time}$

$\rm{distance = 50(x+1 hour)$

The time taken by Mr. Hart to reach to destination is,

$\rm{{Distance}={speed\times time}$

$\rm{distance = 60(x)$

Equating both we get,

$60x = 50(x+1)\\60x = 50x + 50\\60x-50x = 50\\10x = 50\\x = \dfrac{50}{10}\\x=5$

Therefore, they will meet after 5 hours of Mr. hart leaving the town.

so, 9:00a.m. + 5 hours = 2 p.m.

hence, they will meet at 2 p.m.

Learn more time, speed, and distance:

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