The given inequality is:
[tex]|12x-18| \leq 18[/tex]
This inequality can be simplified as:
[tex]-18 \leq 12x-18 \leq 18 \\ \\
-18 + 18 \leq 12x-18+18 \leq 18+18 \\ \\
0 \leq 12x \leq 36 \\ \\
0 \leq x \leq 3[/tex]
So, the solution to the given inequality in Interval Notation is [0,3]
