Question

2.A firecracker is launched vertically from the ground with an initial velocity of 48 ft/sec. (a)
Write a quadratic function h(t) that shows the height, in feet, of the firecracker t seconds after it was launched. Use the general equation h(t) = -16t2 + V + H where Iv is the initial velocity and H is the initial height.

Answer 1

Your equation would be: $h(t)=-16t x^{2} +48t+0.$

You were given the formula for the height of the firecracker. All you need to do in input the known values. The velocity is 48 and that goes where the V is. The initial height is 0 and that goes were the H is. 

You could also leave off the plus 0 at the end.